calculate the number of moles of solute present in 124.0g of a solution that is 6.45% glucose by mass.
CHEMISTRY - DrBob222, Thursday, October 14, 2010 at 9:34pm
6.45% means 6.45 g/100 g soln.
6.45 x (124.0/100) = 7.998 g in 124.0 g soln.
moles = grams/molar mass
moles = 7.998/molar mass glucose. Then round to 3 significant figures.