calculate the number of moles of solute present in 124.0g of a solution that is 6.45% glucose by mass.
6.45% means 6.45 g/100 g soln.
6.45 x (124.0/100) = 7.998 g in 124.0 g soln.
moles = grams/molar mass
moles = 7.998/molar mass glucose. Then round to 3 significant figures.
Why did the mole go to the party? Because it heard there would be plenty of Avogad-bros!
Now, let's calculate the number of moles of solute in your solution. First, we need to determine the mass of glucose in the solution.
Given that the solution is 6.45% glucose by mass, we can calculate the mass of glucose as follows:
Mass of glucose = (6.45/100) × 124.0g
I'm going to grab my calculator because math makes me happier than a clown with a pie:
Mass of glucose = (6.45/100) × 124.0g = 8.003g
Next, we use the molar mass of glucose, which is about 180.16 g/mol, to find the number of moles:
Number of moles = Mass of glucose / Molar mass of glucose
To the math circus! Oh, I mean to the calculation:
Number of moles = 8.003g / 180.16g/mol = 0.0444 mol
So, there are approximately 0.0444 moles of glucose in your 124.0g solution. Enjoy the sweet side of chemistry!
To calculate the number of moles of solute present in a solution, you need to follow these steps:
Step 1: Determine the molar mass of the solute.
The solute in this case is glucose (C6H12O6). To find the molar mass of glucose, you need to add up the atomic masses of all the elements present in one molecule of glucose. The atomic masses are as follows:
C (carbon) = 12.011 g/mol
H (hydrogen) = 1.00784 g/mol
O (oxygen) = 15.999 g/mol
So, the molar mass of glucose is calculated as follows:
(6 x C) + (12 x H) + (6 x O) = (6 x 12.011) + (12 x 1.00784) + (6 x 15.999) = 180.156 g/mol
Step 2: Calculate the mass of solute present in the solution.
The mass percentage is given as 6.45%. This means that there are 6.45 grams of glucose in 100 grams of the solution. To find the mass of glucose in the given 124.0 grams of the solution, we can use the following proportion:
(6.45 g / 100 g) = (X g / 124.0 g)
Cross-multiplying gives:
100 g * X g = 6.45 g * 124.0 g
X g = (6.45 g * 124.0 g) / 100 g = 7.998 g
Step 3: Convert the mass of solute to moles.
To convert the mass of solute (in grams) to moles, divide the mass by the molar mass. In this case, divide the 7.998 grams by the molar mass of glucose, which is 180.156 g/mol.
7.998 g / 180.156 g/mol = 0.0444 moles
Therefore, there are approximately 0.0444 moles of glucose present in the 124.0 g solution.
To calculate the number of moles of glucose (solute) present in the given solution, we need to follow these steps:
1. Determine the mass of glucose in the solution:
Mass of glucose = (Mass of solution) x (Percent composition of glucose)
Mass of glucose = 124.0g x 6.45/100
Mass of glucose = 8.003g
2. Calculate the molar mass of glucose (C₆H₁₂O₆):
The molar mass of glucose (C₆H₁₂O₆) can be found by adding the atomic masses of each element in the molecule:
Carbon (C): 6 x 12.01 g/mol = 72.06 g/mol
Hydrogen (H): 12 x 1.01 g/mol = 12.12 g/mol
Oxygen (O): 6 x 16.00 g/mol = 96.00 g/mol
Molar mass of glucose = 72.06 g/mol + 12.12 g/mol + 96.00 g/mol = 180.18 g/mol
3. Calculate the number of moles of glucose:
Moles of glucose = (Mass of glucose) / (Molar mass of glucose)
Moles of glucose = 8.003g / 180.18 g/mol
Moles of glucose ≈ 0.0444 moles
Therefore, there are approximately 0.0444 moles of glucose solute present in 124.0g of the solution.