a ball is thrown directly upward with a velocity of 40 feet/seconds. its height in feet after t seconds is given by h(t)equals 40t-16t squared
To find the height of the ball after a certain time, we need to substitute the given time value into the equation h(t) = 40t - 16t^2. Let's assume you want to find the height after 3 seconds.
Step 1: Substitute the value of t into the equation.
h(3) = 40(3) - 16(3)^2
Step 2: Simplify the equation.
h(3) = 120 - 16(9)
h(3) = 120 - 144
h(3) = -24
Therefore, the height of the ball after 3 seconds is -24 feet.
Note: The negative height indicates that at 3 seconds, the ball is below the starting point (ground level), which happens when the ball is on its way back down.
To find the height of the ball at a given time, we can use the equation h(t) = 40t - 16t^2.
Step 1: Determine the time at which you want to find the height, let's call it t.
Step 2: Substitute the value of t into the equation to find the height at that time.
Example: Let's find the height of the ball after 2 seconds.
Step 1: t = 2 (given)
Step 2: Substitute t = 2 into the equation h(t) = 40t - 16t^2.
h(2) = 40(2) - 16(2)^2
= 80 - 16(4)
= 80 - 64
= 16 feet
Therefore, the ball is at a height of 16 feet after 2 seconds.