Posted by John on Thursday, October 14, 2010 at 6:22pm.
It depends upon the angle at which the shot is launched. The applied force is not directed along the weight force (vertical) direction.
If we forget about gravity, the applied force times the distance is the work done launching the shot, and that equals the final kinetic energy.
F = (1/2)M V^2/X
That is probably the answer they are looking for.
The actual force is acually higher because the shot putter is also supporting the weight of the shot.
Related Questions
Physics - Estimate the average force exerted by a shot-putter on a 6.5 kg shot ...
physics - A shot-putter moves his arm and the 7.0 kg shot through a distance of ...
physics - A shot-putter moves his arma and the 7kg shot througha distance of 1m...
physics - A shot-‐putter releases the 16 lbs. shot at an angle of...
Physics 1 - A shot-putter puts a shot (weight = 71.3 N) that leaves his hand at ...
Physics - A shot-putter puts a shot (weight = 71.9 N) that leaves his hand at ...
physics - A shot-putter throws the shot ( mass = 7.3 kg) with an initial speed ...
physics to be solved ..easy !! - A shot putter launches a 6.910 kg shot by ...
Physics - no idea all HELP appreciated!! A shot-putter puts a shot (weight = 70....
physics - A shot-putter throws the shot with an initial speed of 15.5m/s at a 34...
For Further Reading
