How many silver atoms are there in 3.88g of silver
2.17*10^22
To determine the number of silver atoms in 3.88g of silver, we need to use the concept of the mole and Avogadro's number.
1. Start by finding the molar mass of silver (Ag):
- The atomic mass of silver (Ag) is approximately 107.87 g/mol.
2. Next, use the molar mass to convert grams of silver to moles:
- Number of moles = Mass (g) / Molar mass (g/mol)
- Number of moles = 3.88g / 107.87 g/mol
The molar mass of silver is 107.87g/mol.
3. Calculate the number of atoms:
- Avogadro's number states that 1 mole of any substance contains 6.022 x 10^23 particles (atoms, molecules, etc.).
- Multiply the number of moles of silver by Avogadro's number to get the number of atoms.
- Number of atoms = Number of moles x Avogadro's number
Number of atoms = (3.88g / 107.87 g/mol) x (6.022 x 10^23 atoms/mol)
Therefore, the number of silver atoms in 3.88g of silver is approximately equal to the calculated value.
To determine the number of silver atoms in 3.88g of silver, we need to use the concept of moles and Avogadro's number.
1. Convert the mass of silver to moles:
First, we need to determine the molar mass of silver (Ag) from the periodic table. The molar mass of silver is approximately 107.87 g/mol.
Use the formula:
Moles = mass / molar mass
Moles of silver = 3.88g / 107.87 g/mol
2. Determine the number of atoms in moles:
Avogadro's number tells us that there are 6.022 x 10^23 atoms in one mole of any substance.
So, the number of atoms in the given amount of silver is:
Number of atoms = Moles of silver x Avogadro's number
Now we can calculate the number of silver atoms in 3.88 grams of silver.
How many moles?
moles = grams/molar mass.
Then there are 6.022 x 10^23 atoms in a mole.