Posted by **Mar** on Thursday, October 14, 2010 at 1:43am.

An object of mass M = 1,284 g is pushed at a constant speed up a frictionless inclined surface which forms an angle θ = 50 degrees with the horizontal. What is the magnitude of the force that is exerted by the inclined surface on the object?

(I'm using 1.284*9.81*cos50 to get the force but I'm still getting a wrong answer.)

Can anyone explain the steps into solving this kind of problem.

- PHYSICS -
**drwls**, Thursday, October 14, 2010 at 2:09am
The normal force depends upon the angle the pushing force is applied to the block. If it is applied parallel to the inclined surface (along the direction of motion), I agree with your equation. Your answer would be in Newtons.

Other force application directions are possible.

- PHYSICS -
**Gharib**, Monday, October 25, 2010 at 1:40pm
Tilt your axis such that, Y is pointing to the opposite of Weight of M. And X is pointing towards the right. (like usual). [The axis shown in the diagram requires you to find Fnet, which I don't know how to find; thus use this method].

In that case,

Positive being up,

-W(of M)+Ncos50=0

=> N=Mg/cos50

plug your numbers, that's your answer.

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