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CHEM- solution/freezing piont

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a solution of sulfur (2.560g) in naphthalene (100g) freezes 0.68K lower the freezing point of pure naphthalene (353.10K). for naphthalene, Kf= 6.8K kg mol. calculatem the molecular formula of the sulfur dissolved in the naphthalene?

  • CHEM- solution/freezing piont - ,

    delta = Kf*molality
    Solve for molality

    molality = moles/kg solvent.
    Solve for moles

    moles = grams/molar mass
    solve for molar mass.

  • CHEM- solution/freezing piont - ,

    so, 0.68K/6.8 K kg mol= 0.1kg/mol (m)
    then 0.1/32g/mol= 3.1*10^-3
    then (3.1*10^-3)*(2.56g)= 8*10^-3
    does that make it S8, i don't get that part.

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