college physics
posted by Alexis .
Arthur (mass 78 kg) and Violet (mass 31 kg) are trying to play on a seesaw. If Violet sits 3.6 m from the fulcrum, at what distance from the fulcrum should Arthur sit?

I am curious what college considers this to be college level.
The product of mass and distance from the fulcrum is the same on both sides, if the seesaw is balanced.
Thus 31 * 3.6 = 78 * X
Solve for X, which will be Arthur's distance in meters. 
So would it be 78*3.6

Ohio State this is my first physics class I have ever taken.

No. The answer is
X = (31*3.6)/78 = 1.43 meters 
Okay thank you for your help.