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March 30, 2015

March 30, 2015

Posted by **Alexis** on Wednesday, October 13, 2010 at 9:48pm.

- college physics -
**drwls**, Wednesday, October 13, 2010 at 10:30pmI am curious what college considers this to be college level.

The product of mass and distance from the fulcrum is the same on both sides, if the seesaw is balanced.

Thus 31 * 3.6 = 78 * X

Solve for X, which will be Arthur's distance in meters.

- college physics -
**Alexis**, Wednesday, October 13, 2010 at 11:07pmSo would it be 78*3.6

- college physics -
**Alexis**, Wednesday, October 13, 2010 at 11:11pmOhio State this is my first physics class I have ever taken.

- college physics -
**drwls**, Wednesday, October 13, 2010 at 11:20pmNo. The answer is

X = (31*3.6)/78 = 1.43 meters

- college physics -
**Alexis**, Wednesday, October 13, 2010 at 11:29pmOkay thank you for your help.

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