Posted by **Alexis** on Wednesday, October 13, 2010 at 9:48pm.

Arthur (mass 78 kg) and Violet (mass 31 kg) are trying to play on a seesaw. If Violet sits 3.6 m from the fulcrum, at what distance from the fulcrum should Arthur sit?

- college physics -
**drwls**, Wednesday, October 13, 2010 at 10:30pm
I am curious what college considers this to be college level.

The product of mass and distance from the fulcrum is the same on both sides, if the seesaw is balanced.

Thus 31 * 3.6 = 78 * X

Solve for X, which will be Arthur's distance in meters.

- college physics -
**Alexis**, Wednesday, October 13, 2010 at 11:07pm
So would it be 78*3.6

- college physics -
**Alexis**, Wednesday, October 13, 2010 at 11:11pm
Ohio State this is my first physics class I have ever taken.

- college physics -
**drwls**, Wednesday, October 13, 2010 at 11:20pm
No. The answer is

X = (31*3.6)/78 = 1.43 meters

- college physics -
**Alexis**, Wednesday, October 13, 2010 at 11:29pm
Okay thank you for your help.

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