Homework Help: physics

Posted by please help! on Wednesday, October 13, 2010 at 8:41pm.

A horizontal rifle is fired at a bull's-eye. The muzzle speed of the bullet is 795 m/s. The barrel is pointed directly at the center of the bull's-eye, but the bullet strikes the target 0.042 m below the center. What is the horizontal distance between the end of the rifle and the bull's-eye?

physics - drwls, Wednesday, October 13, 2010 at 11:31pm
It reaches the target T = X/795 seconds.
Thet time T is the time it takes the bullet to fall H = 0.042 m.
T = sqrt(2H/g)= 0.0926 s

X = 795 T = ___ meters

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