posted by please help! on .
A horizontal rifle is fired at a bull's-eye. The muzzle speed of the bullet is 795 m/s. The barrel is pointed directly at the center of the bull's-eye, but the bullet strikes the target 0.042 m below the center. What is the horizontal distance between the end of the rifle and the bull's-eye?
It reaches the target T = X/795 seconds.
Thet time T is the time it takes the bullet to fall H = 0.042 m.
T = sqrt(2H/g)= 0.0926 s
X = 795 T = ___ meters
A rifle shoots a 4.50g bullet out of its barrel. The bullet has a muzzle velocity of 960m/s just as it leaves the barrel.