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September 1, 2014

September 1, 2014

Posted by **VitaX** on Wednesday, October 13, 2010 at 5:27pm.

- Genereal Physics I -
**VitaX**, Wednesday, October 13, 2010 at 9:49pmI worked on this somewhat and I came to the conclusion that in part a since it's asking for the Power as it passes through its equilibrium position, the force is 0. Which makes the Power 0 Watts. For part b though I'm a little more confused as to how to solve it. I know I need to find Velocity and the force but going about it is a bit tricky.

I did the following:

V = (2k/m)^(1/2) but I'm not sure what value to use for the kinetic energy

Fs = -kd = -640*.68 = -435.2 N

If I can get the right velocity I should be able to finish the problem.

- Genereal Physics I -
**VitaX**, Wednesday, October 13, 2010 at 11:10pmOk, I figured it out. I find the potential energy, and subtract the potential energy from the total energy which was given in the problem. With that kinetic energy now I solve for V using kinetic energy equation. From there I'm able to find the Power with F*V. One of the things that was tricking me up was do I have the displacement negative or not. Apparently I do not, else it's wrong.

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