Posted by Laura on .
A box of mass m with an initial velocity of v0 slides down a plane, inclined at theta with respect to the horizontal. The coefficient of kinetic friction is u. The box stops after sliding a distance x. How far does the box slide?
Solve in terms of Vo, u, etc.
Initial K.E. + loss of P.E. = work done against friction
Put that in equation form:
(1/2)MVo^2 + M*g*X sin theta = M*g costheta*u*X
The mass M cancels out. Solve for X