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A box of mass m with an initial velocity of v0 slides down a plane, inclined at theta with respect to the horizontal. The coefficient of kinetic friction is u. The box stops after sliding a distance x. How far does the box slide?
Solve in terms of Vo, u, etc.

  • Physics -

    Initial K.E. + loss of P.E. = work done against friction

    Put that in equation form:

    (1/2)MVo^2 + M*g*X sin theta = M*g costheta*u*X

    The mass M cancels out. Solve for X

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