When 1.11 g of vanadium is dissolved in HCl, 0.066 g of H2 is produced. Calculate the value of x for the compound VClx produced according to the chemical equation: V = xHCl -> VClx + 0.5x H2
The skeleton equation is
V + HCl --> VCl + H2
1.11 g V = 1.11/50.94 = 0.02179 moles
0.066 g H2 = 0.066/2 = 0.033 moles
That is a ratio of 1V to 1.5 moles H or
2 moles V to 3 moles H2. Therefore, the equation is
2V + HCl ==> 2VCl + 3H2
To make it balance, we need a 6 for HCl and that maks a 3 for 2VCl3.
2V + 6HCl ==> 2VCl3 + 3H2
To find the value of x for the compound VClx, we need to use the given information about the masses of vanadium (V) and hydrogen gas (H2) produced.
1. First, we need to calculate the number of moles of vanadium (V) using its molar mass. The molar mass of vanadium (V) is 50.94 g/mol.
Using the given mass of vanadium (1.11 g), we can calculate the number of moles of vanadium (V) as follows:
moles of V = mass of V / molar mass of V
moles of V = 1.11 g / 50.94 g/mol
2. Next, we need to calculate the number of moles of hydrogen gas (H2) produced using its molar mass. The molar mass of hydrogen (H2) is 2.02 g/mol.
Using the given mass of hydrogen gas (0.066 g), we can calculate the number of moles of hydrogen gas as follows:
moles of H2 = mass of H2 / molar mass of H2
moles of H2 = 0.066 g / 2.02 g/mol
3. Now, since the chemical equation shows that 1 mole of vanadium reacts with 0.5x moles of hydrogen gas, we can set up a proportion using the moles of vanadium (from step 1) and the moles of hydrogen gas (from step 2):
moles of V / [0.5x moles of H2] = 1 / [0.5x]
4. Substitute the calculated values of moles of V and moles of H2 into the proportion:
(1.11 g / 50.94 g/mol) / [0.5x (0.066 g / 2.02 g/mol)] = 1 / [0.5x]
5. Solve the equation for x:
(1.11 g / 50.94 g/mol) / (0.033 g / 2.02 g/mol) = 1 / [0.5x]
Simplifying the equation:
(1.11 g × 2.02 g/mol) / (0.033 g × 50.94 g/mol) = 1 / [0.5x]
From here, you can solve for x by cross-multiplying and simplifying the equation.
By following this process, you can calculate the value of x for the compound VClx produced in the given chemical reaction.