Homework Help: Chemistry

Posted by Anonymous on Tuesday, October 12, 2010 at 9:15pm.

A 5.00 gram sample of aluminum pellets (specific heat capacity = 0.89 J/g*C) and a 10.00 gram sample of iron pellets (specific heat capacity = 0.45 J/g*C) are heated to 100.0 *C. The mixture of hot iron and aluminum is then dropped into 97.3 gram of water at 22.0*C. Calculate the final temperature of the metal and water mixture, assuming no heat loss to the surroundings.

Chemistry - DrBob222, Tuesday, October 12, 2010 at 9:37pm
heat lost by Al + heat lost by Fe + heat gained by water = 0.
[mass Al x specific heat Al x (Tfinal-Tinitial)] + [mass Fe x specific heat Fe x (Tfinal-Tinitial)] + [mass water x speicific heat water x (Tfinal-Tinitial)] = 0
Chemistry - Anonymous, Monday, October 25, 2010 at 5:16pm
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