Posted by **Anonymous** on Tuesday, October 12, 2010 at 9:15pm.

A 5.00 gram sample of aluminum pellets (specific heat capacity = 0.89 J/g*C) and a 10.00 gram sample of iron pellets (specific heat capacity = 0.45 J/g*C) are heated to 100.0 *C. The mixture of hot iron and aluminum is then dropped into 97.3 gram of water at 22.0*C. Calculate the final temperature of the metal and water mixture, assuming no heat loss to the surroundings.

## Answer this Question

## Related Questions

- Chemistry - A 5.00-g sample of aluminum pellets (specific heat capacity = 0.89 J...
- chemistry - a 5.00g sample of Al pellets (specific heat=0.89J/oC*g) and a 10.00g...
- Science-Chemistry - A 5.00 g sample of Al pellets (specific heat = .89 J/g ...
- CHEM - A 5.00 g sample of Al pellets (specific heat = .89 J/g degrees c) and a ...
- CHEM - A 5.00 g sample of Al pellets (specific heat = .89 J/g degrees c) and a ...
- intro chem HELp please - 1. Zinc is often used to calibrate calorimeters because...
- Chemistry - A 54.7-g sample of aluminum at 95.0°C is dropped into 35.0 g of ...
- Science/C - A 250 gram sample of metal is warmed from 50°C to 90°C when 100 ...
- Physcial Science - Hey There, I have 4 questions that I am totally stumped on...
- Physcial Science - Hey There, I have 4 questions that I am totally stumped on...

More Related Questions