the ratio of the length to the width of a rectangle is 5:4. the perimeter of the rectangle is 72 inches. what are the dimensions of the rectangle? i got 40 and 32, am i right?
no, your dimenstion would yield a perimieter of 144
length --- 5x
width --- 4x
so 2(5x+4x) = 72
....
x = 4
length = 5x = 20
width = 4x = 16
the length of rectangle exceeds it's width by 11 inches, and the area is 80 square inches. what are the length and width of the rectangle?
the length of a rectangles exceeds the width by 7cm. if the area is 60cm squares, find the length of the rectangle.
Sudhen
To determine if your answer is correct, let's follow a step-by-step approach to find the dimensions of the rectangle.
Step 1: Understand the problem and set up equations
The problem states that the ratio of the length to the width is 5:4. This means that if we let the width be represented by 'x', the length would be 5x/4.
Step 2: Calculate the perimeter
The perimeter of a rectangle is the sum of all its sides. In this case, the perimeter is given as 72 inches. For a rectangle, the perimeter is twice the sum of the length and width.
Perimeter = 2(length + width)
72 = 2((5x/4) + x)
Simplifying the equation further, we get:
72 = (10x + 8x) / 4
72 = 18x / 4
72 = 9x / 2
144 = 9x
x = 144 / 9
x = 16
Step 3: Find the dimensions
Now that we have the value of 'x' (width), we can substitute it back to find the dimensions.
Width (x) = 16 inches
Length (5x/4) = 5 * 16 / 4 = 20 inches
So, the dimensions of the rectangle are 16 inches (width) and 20 inches (length).
Based on your answer (40 and 32), it seems that you may have multiplied the width and length by 2. However, remember that the ratio given is 5:4, not 10:8. Hence, 40 and 32 aren't the correct dimensions.