Posted by candy on Tuesday, October 12, 2010 at 5:52pm.
this 17% ammonia is to dissolve my chloride ppt
see your original post.
Hi, if I want to prepare a w/v solution, how do I prepare it? Thanks a lot.
If it's the same 69% w/w with a density of 1.42, then we know it is 69g HNO3/100 g soln. 100 g soln has a volume of 70.4 mL so the solution is 69 g x 100/70.4 = 97.98 g/100 mL which I will round to 98 g/100 mL.
We want, say, 10% w/v.
10% w/v means 10 g HNO3/100 mL solution.
We have 98 g/100 mL so we want to take
100 mL x 10/98 = 10.2 mL of the concd solution and make to 100 mL final volume. Check my thinking.
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