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October 1, 2014

October 1, 2014

Posted by **CMM** on Tuesday, October 12, 2010 at 5:13pm.

Please help and explain. I have an exam shortly and a similar question will be on it.

- Calc- Urgent Please -
**Reiny**, Tuesday, October 12, 2010 at 5:46pmIf the base is x by x, let the height be y

Volume = (x^2)y

x^2y = 500

y = 500/x^2

surface area = x^2 + 4xy

= x^2 + 4x(500/x^2 = x^2 + 2000/x

d(surface area)/dx = 2x - 2000/x^2

= 0 for a max/min of surface area

2x - 2000/x^2 = 0

x^3 = 1000

x = 10

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