Posted by **Juliette** on Tuesday, October 12, 2010 at 12:18pm.

5 - sqrt of 20x + 4 >= -3

5- 20x + 4 >= -3

5-4 - 20x >= -3

1 - 20x >= -3-1

-20x >= -4

x<= -15

Possible answers are

x<=3

-1/5 <= x<= 3

x >= -1/5

x >= 0

I think it is -1/5<=x<=3

because both solutions work

- Algebra-Please check -
**Reiny**, Tuesday, October 12, 2010 at 1:19pm
I hate to say this, but each of your lines from

5- 20x + 4 >= -3

5-4 - 20x >= -3

1 - 20x >= -3-1

-20x >= -4

x<= -15

contains an error based on its previous line

First of all , if the question is

5 - √(20x + 4) >= -3 , then

√(20x+4) ≤ 8

consider the equation

√(20x+4) = 8

square both sides

20x+4 = 64

x = 3

so we have the region > 3 and the region < 3

A quick mental consideration in √(20x+4) ≤ 8 will show that only numbers ≤ 3 could work.

finally the inside of the square root cannot be negative,

that is,

20x + 4 ≥0

x ≥ -4/20

x ≥ -1/15

so x has to be between -1/5 and 3 , or

-1/5 ≤ x ≤ 3

- Algebra-Please check -
**Juliette**, Tuesday, October 12, 2010 at 3:18pm
Thank you

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