Posted by pat on Tuesday, October 12, 2010 at 11:50am.
y=x^23x+c and y=kxx^2 meet at
(2,12)
what are the values of c and k??
omg ive tried 100 ways but cant find the correct ans...please help??
Thank You

math  drwls, Tuesday, October 12, 2010 at 12:55pm
"Way" number 101 is easier:
From the first equation and the fact that (2,12) is a solution,
12 = 4 + 6 +c
So c = 2
Similarly, from the second equation, with (2,12) being a solution of that also,
12 = k +2 4
k = 14
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