Posted by **Michelle** on Tuesday, October 12, 2010 at 9:42am.

Could you check these two problems?

3sqrt (y+2) = 3 is y = 25

Answers were: true or false

I said true because I did it like this

Square both sides=y + 2 = 3^3

y+2 = 27

y = 25

and sqrt (2y-6) = 3-y for y

answes are:

no solution

5

3,5

3

I said 3 because I did it like this:

8y -15 + y^2 = 0

y^2 + 8y -15 =0

(y-5) (y+3) = 0

Y = 3,5 but five doesn't work only 3

Can you please check-I didn't put all the steps for the second one-it was too long

- Please check-Reiny -
**Reiny**, Tuesday, October 12, 2010 at 9:54am
you forgot about the 3 in front of 3√(y+2) when you squared

should be

9(y+2) = 9

y+2 = 1

y = -1

check:

LS = 3√(-1+2) = 3√1 = 3

RS = 3

so y = -1

for the second watch your simplifation, my final quadratic was

y^2 - 8y + 15 = 0

(y-3)(y-5) = 0

y = 3 or y = 5

You should have had y = -3

you are right in the conclusion, only x = 3 verifies.

- Thank you Reiny -
**Michelle**, Tuesday, October 12, 2010 at 10:00am
Thanks I think I somewhat get it-Thanks again for the explanations

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