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September 20, 2014

September 20, 2014

Posted by **ARS** on Tuesday, October 12, 2010 at 1:13am.

- physics -
**drwls**, Tuesday, October 12, 2010 at 7:24amThe "effective" acceleration rate, a' , (measured positive downward) as observed in the elevator

satifies the equation

6 = (1/2)a' t^2 = a'/2

since t = 1 second to fall 6 feet)

Therefore a' = 12 ft/s^2

Without elevator acceleration, the observed downward acceleration rate would be g = 32.2 ft/s^2

Since a' = g -a,

where a is the true acceleration rate (downward),

a = 32.2 - 12 = 20.2 ft/s^2

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