Posted by ARS on Tuesday, October 12, 2010 at 1:13am.
The "effective" acceleration rate, a' , (measured positive downward) as observed in the elevator
satifies the equation
6 = (1/2)a' t^2 = a'/2
since t = 1 second to fall 6 feet)
Therefore a' = 12 ft/s^2
Without elevator acceleration, the observed downward acceleration rate would be g = 32.2 ft/s^2
Since a' = g -a,
where a is the true acceleration rate (downward),
a = 32.2 - 12 = 20.2 ft/s^2
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