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the length of a rectangular jewlery box is 6 inches more than twice the width. the perimeter is 54 inches find length and width.

  • algebra - ,

    Solve the following:
    L = 2W + 6
    2(L + W) = 54

    Rewrite them as:
    2W + 2L = 54
    2W - L = -6
    Subtract the last equation from the third equation. You get an equation in L only.
    3L = 60.
    Take it from there.

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