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October 1, 2014

October 1, 2014

Posted by **mary** on Monday, October 11, 2010 at 11:55pm.

I. a test score of 13

II. a test score of 59

- college, statistics -
**TutorCat**, Tuesday, October 12, 2010 at 2:42amz = (x - mean)/(standard deviation)

- college, statistics -
**mary**, Tuesday, October 12, 2010 at 11:30amhow is the problem worked out?

- college, statistics, z score -
**cat**, Wednesday, October 13, 2010 at 7:05pmhey cat:

thank you for the information. so clarify i would just plug in the test scores such as 13 and 59 for the x value and 43 for mean with 17.0 for the standard deviation to come up with the following :

z=(13-43)/17.0= 10.47058824 to round off to 10.0?

z= (59-43)/17.0=56.47058824, round off to ?

please coonfirm and show where i went wrong. thank you very much.

mary

- college, statistics -
**Nneka**, Wednesday, March 9, 2011 at 1:44amZ=(13-43)/17=-1.76

Z=(59-43)/17=0.94

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