Posted by **hana** on Monday, October 11, 2010 at 11:12pm.

A stone is thrown vertically upward with a speed of 11.5 m/s from the edge of a cliff 95.0 m high.

(a) How much later does it reach the bottom of the cliff?

(b) What is its speed just before hitting?

(c) What total distance did it travel?

For (c), the right answer is 108.46 m. I really need help on parts (a) and (b) please!

- physics -
**drwls**, Monday, October 11, 2010 at 11:49pm
(a) Solve this for time t:

Y = 11.5 t -4.9 t^2 = -95

(b) V^2(final) - V^2(initial) = 2 g H

(Easily derived using conservation of energy)

H is the distance the stone falls, 95 m

(c) You said you got this already. It would be twice the distance it goes up (since it comes back down), plus 95m

Total distance = (V^2/g) + H

## Answer this Question

## Related Questions

- science - A stone is thrown vertically upward with a speed of 11.0 m/s from the ...
- physics - a stone is thrown vertically upward with a speed of 10.5 m/s from the ...
- physics - A stone is thrown vertically upward with a speed of 10.0 m/s from the ...
- Physics - A stone is thrown vertically upward with a speed of 12.0 m/s from the ...
- physics - A stone is thrown vertically upward with a speed of 11.5 m/s from the...
- physics - A stone is thrown vertically upward with a speed of 11.5 m/s from the ...
- physics for physical science - A stone thrown vertically upwards with a speed ...
- physics - a stone is thrown vertically upward at a speed of 10 m/s from a cliff ...
- physics - A stone is thrown vertically upward with a speed of 14.0 m/s from the ...
- physics - A rock is thrown vertically upward from the edge of a cliff. The rock ...

More Related Questions