and elevator lifts five passengers 30 m in 24 sec. the power is 15000 w. what is the total weight of the elevator and passengers? ha know that?

To determine the total weight of the elevator and passengers, we need to calculate the force exerted by the elevator and then convert it to weight.

First, let's find the force exerted by the elevator. We can use the formula: Power = Force x Velocity. Given that the power is 15000 W and the velocity is the distance traveled divided by the time taken, we can calculate the force:

Force = Power / Velocity
Force = 15000 W / (30 m / 24 sec) = 15000 W / (1.25 m/s) = 12000 N

Now that we have the force exerted by the elevator, we can convert it to weight using Newton's second law, which states that weight is equal to the mass of an object multiplied by the acceleration due to gravity. Since weight = mass x gravity and the acceleration due to gravity is approximately 9.8 m/s^2, we can solve for the mass:

Weight = Mass x Gravity
Mass = Weight / Gravity
Mass = 12000 N / 9.8 m/s^2 ≈ 1224 kg

Therefore, the total weight of the elevator and passengers is approximately 1224 kg.