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The space shuttle releases a satellite into a circular orbit 440 km above the Earth. How fast must the shuttle be moving (relative to Earth) when the release occurs?

  • Physics -

    V^2/R = GM/R^2 for circular orbits.

    Solve for V

    R is the distance from the CENTER of the earth. You will need the Earth's radius, 6378 km. For R, add 440 to that and convert to meters.

    G is the universal gravity constant. Get to know it.

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