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December 20, 2014

December 20, 2014

Posted by **Lyri** on Monday, October 11, 2010 at 12:24pm.

Solve using the elimination method. Show your work. If the system has no solution or an infinite number of solutions, state this.

-2x Ð 8y = 22

-6x Ð y = 20

At first I tried to multiply by 8 but that did not work.

- Intermediate Algebra (Math) -
**MathMate**, Monday, October 11, 2010 at 2:40pmI assume the illegible sign is a + sign, since the - sign shows clearly.

-2x + 8y = 22 ....(1)

-6x + y = 20 ....(2)

First, we determine if the system has 0 solution, one solution or many solutions.

Calculate the determinant of the left-hand-side:

Δ=(-2)(1)-(-6)(8)=46

Since Δ≠0, the system has one solution. Multiplying 3*(-1) and add to (2) gives

-23y=-46

solving for y gives

y=2

Substitute y=2 into either (1) or (2) to solve for x.

Then substitute both x and y in the remaining equation for a check.

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