PHYSICS HELP!
posted by Jen on .
The space shuttle releases a satellite into a circular orbit 700 km above the Earth. How fast must the shuttle be moving (relative to Earth) when the release occurs?

First you must find the Force of Gravity usin5g Fg=Gm1/r^2
G=6.67E11
m1= mass of the earth: 5.9736E24
r= (radius of earth plus the radius of sattelite released)
radius of earth = 6,371,000m + 700,000m = 7,071,000
Fg=(6.67E11)(5.9736E24)/(7071000^2)
Fg= 7.97
Next you must find the velocity necessary for centripetal acceleration to equal the force of gravity that you just found.
7.97=v^2/r
7.97=v^2/7,071,000
56355870=v^2
take the square root
v=7507 m/s