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PHYSICS ---HELP!

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The space shuttle releases a satellite into a circular orbit 700 km above the Earth. How fast must the shuttle be moving (relative to Earth) when the release occurs?

  • PHYSICS ---HELP! - ,

    First you must find the Force of Gravity usin5g Fg=Gm1/r^2

    G=6.67E-11
    m1= mass of the earth: 5.9736E24
    r= (radius of earth plus the radius of sattelite released)
    radius of earth = 6,371,000m + 700,000m = 7,071,000

    Fg=(6.67E-11)(5.9736E24)/(7071000^2)
    Fg= 7.97

    Next you must find the velocity necessary for centripetal acceleration to equal the force of gravity that you just found.

    7.97=v^2/r
    7.97=v^2/7,071,000
    56355870=v^2
    take the square root
    v=7507 m/s

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