When 0.016 moles of lead(II) nitrate are dissolved in enough water to make 748 mililiters of solution, what is the molar concentration of nitrate ions?
Answer in units of M.
To find the molar concentration of nitrate ions, we need to know the number of moles of nitrate ions present in the given amount of lead(II) nitrate solution.
First, let's determine the number of moles of nitrate ions in 0.016 moles of lead(II) nitrate.
Lead(II) nitrate has the chemical formula Pb(NO3)2. From the formula, we can see that there are two nitrate ions (NO3-) for every one molecule of lead(II) nitrate.
So, the number of moles of nitrate ions present in the solution is:
0.016 moles x 2 = 0.032 moles
Next, we need to calculate the molar concentration of the nitrate ions.
The molar concentration (Molarity) is given by the equation:
Molarity = moles of solute / volume of solution (in liters)
The volume of the solution is given as 748 milliliters, which can be converted to liters by dividing by 1000:
Volume = 748 ml / 1000 = 0.748 L
Now, we can substitute the values into the equation:
Molarity = 0.032 moles / 0.748 L
Calculating this, we get:
Molarity = 0.0428 M
Therefore, the molar concentration of nitrate ions in the solution is 0.0428 M.
To find the molar concentration of nitrate ions, we need to determine the number of moles of nitrate ions in the given amount of lead(II) nitrate.
The formula for lead(II) nitrate is Pb(NO₃)₂. This means that for every 1 mole of Pb(NO₃)₂, there are 2 moles of nitrate ions (NO₃⁻).
Given that we have 0.016 moles of Pb(NO₃)₂, we can multiply this value by the ratio of nitrate ions to Pb(NO₃)₂ to find the number of moles of nitrate ions.
Number of moles of nitrate ions = 0.016 moles Pb(NO₃)₂ * (2 moles NO₃⁻ / 1 mole Pb(NO₃)₂)
Number of moles of nitrate ions = 0.032 moles NO₃⁻
Next, we need to determine the volume of the solution in liters. The given volume is 748 milliliters, which is equivalent to 0.748 liters.
Finally, we can calculate the molar concentration of nitrate ions (NO₃⁻) by dividing the number of moles of nitrate ions by the volume of the solution in liters.
Molar concentration of nitrate ions = 0.032 moles NO₃⁻ / 0.748 liters
Molar concentration of nitrate ions = 0.042 M (rounded to three decimal places)
Therefore, the molar concentration of nitrate ions in the solution is 0.042 M.