Chemistry
posted by Mike on .
How many grams of sucrose (C12H22O11)
must be dissolved in 200 g water to make a solution in which the mole fraction of sucrose is 0.2?
Answer in units of g.

MOL FRACTION H2O + MOL FRACTION C12H22O11 = 1
THEN
MOL FRACTION H2O = 0.8
MOL FRACTION H2O = MOL H20 / TOTAL MOL
MOL H2O = 200/18 = 11.1
THEN
0.8=11.1/(11.1+MOL C12H22O11)
MOL C12H22O11 = 0.26MOL
MASS OF C12H22O11 = MOL * MOLAR MASS
MASS OF C12H22O11 =0.26*342
MASS OF C12H22O11 = 88.92 GRAM