KCl+Pb(C2H3O2)2==>?
PbCl2 + KC2H3O2. Must be balanced.
To determine the reaction between KCl and Pb(C2H3O2)2, you need to use the guidelines for writing balanced chemical equations. Here's how you can get the answer:
Step 1: Identify the reactants and products. In this case, the reactants are KCl (potassium chloride) and Pb(C2H3O2)2 (lead(II) acetate).
Step 2: Write the correct chemical formulas for the reactants and products. The formula for potassium chloride is KCl, and the formula for lead(II) acetate is Pb(C2H3O2)2.
Step 3: Determine the products of the reaction. To do this, we combine the elements from the reactants so that they form new compounds. In this case, K (potassium) will pair with C2H3O2 (acetate) to form KC2H3O2 (potassium acetate), and Pb (lead) will pair with Cl (chloride) to form PbCl2 (lead(II) chloride).
Step 4: Write the balanced chemical equation by placing the reactants on the left side and the products on the right side. Thus, the balanced equation for the reaction is:
2 KCl + Pb(C2H3O2)2 → 2 KC2H3O2 + PbCl2
In this balanced equation, it specifies that two molecules of KCl react with one molecule of Pb(C2H3O2)2, yielding two molecules of KC2H3O2 and one molecule of PbCl2.
Overall, the reaction between KCl and Pb(C2H3O2)2 is a double displacement reaction, where the positive ions of one compound (K+ and Pb2+) exchange places with the positive ions of the other compound (C2H3O2- and Cl-).