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March 25, 2017

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Naturally occuring boron is 80.20% boron-11 and 19.80% of some other isotopic form of boron. What must be the atomic mass of this second isotope be in order to account for the 10.81 amu average atomic mass for boron?

  • chemistry - ,

    Do you have the mass of B-11?
    Let X = mass B-X , then,

    0.8020(mass B-11) + 0.1980(X) = 10.81
    Substitute mass B-11 and solve for X

  • chemistry - ,

    10.0amu

  • chemistry - ,

    b is for b and d is for ak

  • chemistry - ,

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