Posted by **Kavi** on Sunday, October 10, 2010 at 6:31pm.

You are given a vector in the xy plane that has a magnitude of 100.0 units and a y component of -50.0 units

(b) Assuming the x component is known to be positive, specify the vector which, if you add it to the original one would give a resultant vector that is 85.0 units long and points entirely in the -x direction.

Magnitude ?

Direction ?

- physics honors -
**Henry**, Monday, October 11, 2010 at 1:18am
Y = ver = -50 (given),

X^2 + (-50)^2 = (100)^2,

X^2 = 10000 - 2500 = 7500,

X = hor = sqrt(7500) = 86.6,

Vector to be added:

-50 + Y = 0,

Y = 50 added.

86.6 + X = -85,

X = hor = -85 - 86.6 = -171.6 added.

tanA = Y/X = 50/171.6 = 0.2914,

A = 16.24 deg.

Magnitude = y / sinA = 50/sin16.24

= 178.7

Direction = 16.24 deg above WEST.

- physics honors -
**Henry**, Monday, October 11, 2010 at 5:19pm
Correction:

Direction = 16.24 deg NORTH of WEST.

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