Posted by Mikky on Sunday, October 10, 2010 at 6:30pm.
The heat required to raise the beaker temperature will be 3/4 as much the second time, becasue of the delta-T rTIO. The heat required to heat the liquid will be higher by a factor (200/250)(2.43/0.67) = 2.90
Calculate the total heat required in the second case. The ratio (heat)2/(heat1) wilL be the ratio of the heating times required, assuming the heaT transfer rate of the burner is the same.
i dont get this, could you explain in details or could u tell me the ans. so i could verify my answer. thanks
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