9x^2+4y^2 factoring strategy solution if there is a prime say so - ty:)
i don't know if this is what you're looking for, but i got y=3x+2
Hi Jen -
Can you explain how you received this as I have been working this problem for most of the day and have not come to that conclusion? ty:)
To factor the expression 9x^2 + 4y^2, we can use a factoring strategy called the difference of squares.
The difference of squares states that for any two terms in the form a^2 - b^2, we can factor it as (a + b)(a - b).
In this case, we have 9x^2 + 4y^2. Notice that 9x^2 is a perfect square because it's the square of 3x (3x * 3x). Similarly, 4y^2 is a perfect square because it's the square of 2y (2y * 2y).
So, we can write the expression as the difference of squares:
9x^2 + 4y^2 = (3x)^2 - (2y)^2
Using the difference of squares formula, we can factor it as:
(3x + 2y)(3x - 2y)
Therefore, the factored form of 9x^2 + 4y^2 is (3x + 2y)(3x - 2y).
Note: There are no prime factors in this expression.