What volume of 0.174M Na3PO4 solution is necessary to completely react with 89.1mL of 0.106M CuCl2?

2Na3PO4(aq) + 3CuCl2(aq) produces Cu3(PO4)2(s)+ 6NaCl(aq)

Here is a sample stoichiometry problem. Just follow the steps. moles = M x L.

http://www.jiskha.com/science/chemistry/stoichiometry.html

To find the volume of the Na3PO4 solution necessary to react with the given volume of CuCl2 solution, we can use the concept of stoichiometry.

Stoichiometry is a method used to calculate the quantities of reactants and products involved in a chemical reaction. It allows us to relate the amounts of different substances in a balanced chemical equation.

In this case, the balanced chemical equation is:

2Na3PO4(aq) + 3CuCl2(aq) → Cu3(PO4)2(s) + 6NaCl(aq)

From the equation, we can see that the stoichiometric ratio between Na3PO4 and CuCl2 is 2:3. This means that 2 moles of Na3PO4 react with 3 moles of CuCl2.

Here's how we can calculate the volume of Na3PO4 solution:

1. Convert the given volume of CuCl2 solution from mL to L:
89.1 mL = 89.1 / 1000 L = 0.0891 L

2. Determine the number of moles of CuCl2 using its concentration and volume:
moles of CuCl2 = concentration × volume
moles of CuCl2 = 0.106 M × 0.0891 L = 0.00947 moles

3. Use the stoichiometric ratio to find the number of moles of Na3PO4:
3 moles of CuCl2 reacts with 2 moles of Na3PO4
Therefore, the number of moles of Na3PO4 = (2 moles / 3 moles) × 0.00947 moles = 0.00631 moles

4. Find the volume of Na3PO4 solution using its concentration and the number of moles:
moles of Na3PO4 = concentration × volume
0.00631 moles = 0.174 M × volume
Therefore, volume = 0.00631 moles / 0.174 M = 0.036 L = 36 mL

So, the volume of a 0.174 M Na3PO4 solution necessary to completely react with 89.1 mL of 0.106 M CuCl2 is 36 mL.