The speed of a train increased from 15 mi/hr to 25 mi/hr in a distance of 500 ft. Calculate the average acceleration in ft/s2.

Vf^2=Vi^2+2ad

solve for a

To calculate the average acceleration, we need to use the formula:

acceleration = (final velocity - initial velocity) / time

However, in this question, we are given the change in speed and distance, but not the time. To handle this, we need to first find the time it took for the train's speed to change.

We know that acceleration is defined as the change in velocity over time. In this case, the change in velocity is (25 mi/hr - 15 mi/hr = 10 mi/hr).

Next, we need to convert the distance from feet to miles since velocity is given in miles per hour. There are 5280 feet in a mile, so 500 ft is equivalent to (500 ft / 5280 ft/mi) = approximately 0.0947 miles.

Now, we can substitute our values into the formula and solve for time:

acceleration = (10 mi/hr) / time

0.0947 miles = (10 mi/hr) * time

time = 0.0947 miles / (10 mi/hr)

time = 0.00947 hours

Now, we can substitute the values of initial velocity, final velocity, and time into the acceleration formula:

acceleration = (25 mi/hr - 15 mi/hr) / (0.00947 hours)

acceleration = 10 mi/hr / 0.00947 hours

acceleration ≈ 1056.58 ft/s²

Therefore, the average acceleration of the train is approximately 1056.58 ft/s².