Posted by Me on .
A 60 kg skier with an initial speed of 12 m/s coasts up a 2.5 m high rise that makes a 35 degree angle with the horizontal. If the coefficient of friction between the skis and the snow is .08, find the speed of the skier when he reaches the top of the rise.
How much work does friction do on the skier?
This is a conservation of energy type of problem!

physics 
bobpursley,
The work done on friction=mu*mgCos35*2.5/sin35
change of PE=mg*2.5
InitialKE=FinalKEchangePEfrictionwork
find the final speed. 
physics 
Devin,
The final formula should read
FinalKE= InitialKeChangePEWfriction
hope this helps anyone doing this problem for homework!