Zandor is being shot out of his cannon (at a velocity of 40 m/s) at an angle of 40 degrees above the horizontal. He is planning to pass through a ring of fire (which is 60 m from where he starts) to the landing pad. How far is the ring of fire from the ground? How far is the landing pad from where he starts?

Question

Zandor is being shot out of his cannon (at a velocity of 40 m/s) at an angle of 40 degrees above the horizontal. He is planning to pass through a ring of fire (which is 60 m from where he starts) to the landing pad. How far is the ring of fire from the ground? How far is the landing pad from where he starts?

Answer 1

time to go 60 m

time=60/40cos40

now, how high at that time?

h=40sin40*t-4.9t^2

landing pad?
find the time of impact
hf=Vsin40t-4.9t^2 when hf=0,solve for time.
then, distance=40cos40*t