A motorcycle and 66.0 kg rider accelerate at 2.0 m/s2 up a ramp inclined 5.0° above the horizontal. What are the magnitude of (a) the net force on the rider and (b) the force on the rider from the motorcycle?

Net forceon rider=massrider*acceleration.

Now, that same force is from the motorcycle, otherwise, how would the rider move?

hows that it doesnt work whats the full equation?

Hmmm.

Surely the question is not wanting to add the force of gravity (weight) downward.
I don't know what the problem is wanting.

they are asking to get the force on the rider from the bike nd it is not the same as the rider net force on the

To calculate the magnitude of the net force on the rider and the force on the rider from the motorcycle, we can start by breaking down the forces acting on the rider.

Let's define a coordinate system where the ramp's surface is the x-axis and the vertical direction is the y-axis. We'll also assume that there is no friction between the motorcycle and the ramp.

(a) Magnitude of Net Force on the Rider:
The forces acting on the rider along the x-axis are the force of gravity (mg) pulling downward and the force of the motorcycle pushing upward. The force of gravity can be broken down into two components: one along the x-axis (mg*sinθ) and one along the y-axis (mg*cosθ), where θ is the angle of inclination (5.0°).

The net force on the rider along the x-axis is the difference between the force of the motorcycle and the component of gravity along the x-axis:

F_net_x = F_motorcycle - (mg*sinθ)

Substituting the given values:
F_motorcycle = mass_rider * acceleration
F_net_x = (mass_rider * acceleration) - (mass_rider * g * sinθ)

(b) Force on the Rider from the Motorcycle:
Since the motorcycle and the rider are connected, the force exerted by the motorcycle on the rider is in the same direction as the net force on the rider. Therefore, the force on the rider from the motorcycle is equal to the net force on the rider along the x-axis:

F_motorcycle_rider = F_net_x

Substituting the expression for F_net_x, we have:
F_motorcycle_rider = (mass_rider * acceleration) - (mass_rider * g * sinθ)

Now we can calculate the values using the given information:
- Mass of the rider (m): 66.0 kg
- Acceleration (a): 2.0 m/s^2
- Angle of inclination (θ): 5.0°
- Acceleration due to gravity (g): 9.8 m/s^2

(a) Magnitude of Net Force on the Rider:
F_net_x = (66.0 kg * 2.0 m/s^2) - (66.0 kg * 9.8 m/s^2 * sin(5.0°))

(b) Force on the Rider from the Motorcycle:
F_motorcycle_rider = (66.0 kg * 2.0 m/s^2) - (66.0 kg * 9.8 m/s^2 * sin(5.0°))

Calculating these values will give you the magnitude of the net force on the rider and the force on the rider from the motorcycle.