A certain force gives an object of mass m1 an acceleration of 13.0 m/s2 and an object of mass m2 an acceleration of 2.10 m/s2. What acceleration would the force give to an object of mass (a)m2 – m1 and (b)m2 + m1?

(a) 13 = F/m1

2.1 = F/m2
m2/m1 = 13/2.1 = 6.19

F/(m2 - m1) = F/[m2(1 -(m1/m2)]
= (F/m2)/(1 -0.1615) = 2.1/(0.8385)
= 2.5 m/s

(b) F/(m1 + m2) = F/[m2(1 +(m1/m2)]
You finish it.

i keep on having b) wrong even when replacing

(b) F/(m1 + m2) = F/[m2(1 +(m1/m2)]

= F/m2*[1/(1 + 0.1615)]
= 2.1*/1.1615 = 1.81 m/s^2

To find the acceleration that the force would give to an object of mass (a) m2 - m1 and (b) m2 + m1, we can use Newton's second law of motion:

F = m * a

where F is the force, m is the mass of the object, and a is the acceleration.

Here, we are given two scenarios:

For the first scenario, the force gives an object of mass m1 an acceleration of 13.0 m/s^2.
For the second scenario, the force gives an object of mass m2 an acceleration of 2.10 m/s^2.

Let's calculate the force in each scenario:

For the first scenario:
F1 = m1 * a1
Given that a1 = 13.0 m/s^2

For the second scenario:
F2 = m2 * a2
Given that a2 = 2.10 m/s^2

Now, let's calculate the acceleration for an object of mass (a) m2 - m1 and (b) m2 + m1 using the calculated forces.

(a) For m2 - m1:
Using Newton's second law for the first scenario:
F1 = (m2 - m1) * a [1]

We can rearrange equation [1] to solve for acceleration (a):
a = F1 / (m2 - m1)

(b) For m2 + m1:
Using Newton's second law for the second scenario:
F2 = (m2 + m1) * a [2]

We can rearrange equation [2] to solve for acceleration (a):
a = F2 / (m2 + m1)

Now, using the given values, calculate the acceleration for each scenario.