An electron with a speed of 1.3 × 107 m/s moves horizontally into a region where a constant vertical force of 4.4 × 10-16 N acts on it. The mass of the electron is 9.11 × 10-31 kg. Determine the vertical distance the electron is deflected during the time it has moved 29 mm horizontally.

There is vertical acceleration

ay = F/m = 4.83*10^14 m/s^2

The time it takes to move 29 mm = 0.029 m horizontally is
T = 0.029 m/1.3*10^7s = 2.23*10^-9 s

The vertical distance moved is

Y = (1/2)*ay*T^2 = 2.4*10-3 m = 2.4 mm

its giving me a wrong answear can u check again plz

it is giving me 0.0024m as a wrong answer

THANKS!!!

To determine the vertical distance the electron is deflected, we need to use the equations of motion.

First, we can calculate the time it takes for the electron to move 29 mm horizontally. The given speed of the electron is 1.3 × 10^7 m/s. Therefore, the time taken can be calculated using the formula:

Time = Distance / Speed
Time = (29 × 10^-3 m) / (1.3 × 10^7 m/s)

Now that we have the value of time, we can use the equations of motion to calculate the vertical distance the electron is deflected. Since the electron experiences a constant vertical force, it will undergo vertical acceleration.

The equation to calculate the vertical distance is given by:

Vertical distance = (1/2) * acceleration * time^2

To calculate the vertical acceleration, we can use Newton's second law, which states:

Force = mass * acceleration

Rearranging the equation, we get:

Acceleration = Force / mass

Substituting the given values, we have:

Acceleration = (4.4 × 10^-16 N) / (9.11 × 10^-31 kg)

Now we can substitute the values of time and acceleration into the equation for vertical distance to find the answer.