Posted by Amber on Saturday, October 9, 2010 at 12:34am.
<< Three blocks are connected on the table as shown below. >>
Where?
Im sorry, m1 is suspended by a pulley and string on the left side, m2 is on the table connected to the pulley by a string in the middle and m3 is suspended on the right side by a pulley and string which is also connected to m2.
I am pretty sure I need to find an equation in terms of m, a, and kinetic friction so I will only have one unknown. From my fbd I figured that the normal force would not equal the weight in the y direction because it is accelerating down. So I dont know how to come up with that equation to solve for a and T.
The next thing I tried was to solve for T from by fbd. I got T=m1g-m1a for the first mass, then T1-T2=-fk*m2g+m1a for the second, and T=m3g+m3a. I dont know if this is right or not. Since I am trying to find the acceleration of each mass can i set these equations equal to each other? That would find the acceleration of the whole system. I just cant figure this out.
that still doesnt work...this is SOOOOOOOOOOOOOOO frustrating
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