posted by Amber on .
Three blocks are connected on the table as shown below. The coefficient of kinetic friction between the block of mass m2 and the table is 0.400. The objects have masses of m1 = 3.00 kg, m2 = 1.45 kg, and m3 = 1.90 kg, and the pulleys are frictionless. Determine the acceleration of each object, including its direction.Determine the tensions in the two cords.
<< Three blocks are connected on the table as shown below. >>
Im sorry, m1 is suspended by a pulley and string on the left side, m2 is on the table connected to the pulley by a string in the middle and m3 is suspended on the right side by a pulley and string which is also connected to m2.
I am pretty sure I need to find an equation in terms of m, a, and kinetic friction so I will only have one unknown. From my fbd I figured that the normal force would not equal the weight in the y direction because it is accelerating down. So I don't know how to come up with that equation to solve for a and T.
The next thing I tried was to solve for T from by fbd. I got T=m1g-m1a for the first mass, then T1-T2=-fk*m2g+m1a for the second, and T=m3g+m3a. I don't know if this is right or not. Since I am trying to find the acceleration of each mass can i set these equations equal to each other? That would find the acceleration of the whole system. I just cant figure this out.
that still doesnt work...this is SOOOOOOOOOOOOOOO frustrating