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November 27, 2014

November 27, 2014

Posted by **Andres** on Friday, October 8, 2010 at 11:04pm.

How long is the rock in the air, from the instant it is released until it hits the bottom of the hole?

- physics -
**drwls**, Saturday, October 9, 2010 at 7:39amAt the bottom of the hole, kinetic energy is increased by M g D from the original value. D is the depth.

Therefore V2^2/2 - V1^2.2 = g D

(The mass cancels out).

Solve for V2, which will be negative (going down)

V1 is the initial upward velocity

For the time in the air, T, solve

V1*T - (g/2)T^2 = -17.3 meters

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