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Calcium carbonate CaCO3 reacts with stomach acid (HCl, hydrochloric acid) according to the following equation:
CaCO3(s)+2HCl(aq)->CaCl2(aq)+H2O(l)+CO2(g)
Tums, an antacid, contains CaCO3.
If Tums is added to 35.0 mL of 0.300 M HCl,how many grams of CO2 gas are produced?

  • chemistry - , Friday, October 8, 2010 at 10:53pm

    Here is a sample problem I've posted on simply stoichiometry. Just follow the steps. moles in this case = M x L.
    http://www.jiskha.com/science/chemistry/stoichiometry.html

  • chemistry - , Saturday, October 9, 2010 at 12:09am

    do i still need to find whether CaCO3 or HCl is the limiting reactant?

  • chemistry - , Saturday, October 9, 2010 at 12:25am

    To be a limiting reagent type problem BOTH reactants must be given; i.e., you have 35.0 mL of 0.300 M HCl (one of the reactants) but you don't have the other one (only that it is TUMS but no mass is given nor a percent composition--I thing the assumption is that you have enough CCO3 to use all of the HCl).
    moles HCl = 0.035 x 0.300 = 0.0105

    Convert moles HCl to moles CO2 using the coefficients in the balanced equation.
    0.0105 moles HCl x (1 mole CO2/2 moles HCl) = 0.0105 x (1/2) = 0.00525
    Now convert moles CO2 to grams.
    g = moles x molar mass = ?? grams CO2.

  • chemistry - , Saturday, October 9, 2010 at 12:50am

    thanks...

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