Posted by katelyn on Friday, October 8, 2010 at 7:43pm.
horizontal: 33=V*time
vertical: 0=1.5-1/2 9.8 t^2
solve the first equation for time
time=33/V
Put that in the second equation for t.
Solve for V.
Dvide 33 m by the time it takes the arrow to fall 1.5 meters. Call bhat time T.
That time of flight T is obtainable from the relation:
1.5 = (g/2)T^2.
T = sqrt(3.0/g) = 0.553 s
33 m/0.553s = ___ m/s
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