Posted by ashley on Friday, October 8, 2010 at 7:34pm.
original friction= 200N
reduce by .19%: 162N
weight increased by 42%, increases friction by 1.42
new horizontal force: 200*.81*1.41
i don't quite understand how you reduced 200N to 162N ?
81% of 200 N is 162 N, the new rolling friction force if the weight stayed the same. You must also account for the higher weight.
The 1.41 in Mr. Pursley's final formula should be 1.42
thank you so much this really helps :)
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