I have some questions regarding motion problems.

If I have a ball at initial velocity of 50m/s at 35 degree angle, to find horizontal and vertical components, I do the following:
Vertical is 50(sin35)=28.68-rounded to 29
Horizontal = 50 (cos 35)=40.96-rounded to 42
Maximum height ball hit 29 m/s^2 /2(9.81m/s^2)= 42.90
Range of ball:29/4.92 = 5.9 s
take 41 (horizontal velocity) times 2 =84 meters

Could you just check this for me-thank you-if its wrong, just direct me where I did it incorrectly

Just please check my calculations-

Yes, I agree, but I would not have rounded to two significant figures, it pains me to to do that.

Hi, I think I did the range calculation incorrectly-Shouldn't I have done:

Horizontal 40.96 times 5.9 s, not 2-I'm not sure where I got the two
My new answer should be 40.96 x 5.9 = 241.66m

I'll remember about rounding

yes, I missed that on the time.

Thanks for your help I really appreciated it!!

To solve this problem, you correctly used the equations for finding the horizontal and vertical components of initial velocity. Let's go through the steps together to verify the answers.

Given:
Initial velocity (v0) = 50 m/s
Launch angle (θ) = 35 degrees
Acceleration due to gravity (g) = 9.81 m/s^2

To find the vertical component (Vy) of the initial velocity:
Vy = v0 * sin(θ)
Vy = 50 * sin(35)
Vy ≈ 28.68 m/s (rounded to 29 m/s)

To find the horizontal component (Vx) of the initial velocity:
Vx = v0 * cos(θ)
Vx = 50 * cos(35)
Vx ≈ 40.96 m/s (rounded to 42 m/s)

Now, let's check the calculations for the maximum height and the range of the ball.

To find the maximum height, use the equation:
Max height = (Vy^2) / (2g)
Max height ≈ (29^2) / (2 * 9.81)
Max height ≈ 42.9 m (rounded to 43 m)

To find the time of flight (T) or the total time ball spends in the air, you can use the vertical component (Vy):
T = Vy / g
T = 29 / 9.81
T ≈ 2.96 s (rounded to 3 s)

To find the range, multiply the horizontal component (Vx) by the time of flight (T):
Range = Vx * T
Range = 42 * 3
Range = 126 m (not 84 m as stated)

Therefore, the range of the ball is estimated to be 126 meters.

In summary:
Vertical component (V