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March 31, 2015

March 31, 2015

Posted by **Katherine** on Friday, October 8, 2010 at 3:59pm.

If I have a ball at initial velocity of 50m/s at 35 degree angle, to find horizontal and vertical components, I do the following:

Vertical is 50(sin35)=28.68-rounded to 29

Horizontal = 50 (cos 35)=40.96-rounded to 42

Maximum height ball hit 29 m/s^2 /2(9.81m/s^2)= 42.90

Range of ball:29/4.92 = 5.9 s

take 41 (horizontal velocity) times 2 =84 meters

Could you just check this for me-thank you-if its wrong, just direct me where I did it incorrectly

- Physics-above question -please check it -
**Katherine**, Friday, October 8, 2010 at 4:00pmJust please check my calculations-

- Physics -
**bobpursley**, Friday, October 8, 2010 at 4:29pmYes, I agree, but I would not have rounded to two significant figures, it pains me to to do that.

- Physics-I think I did range wrong-please check -
**Katherine**, Friday, October 8, 2010 at 4:36pmHi, I think I did the range calculation incorrectly-Shouldn't I have done:

Horizontal 40.96 times 5.9 s, not 2-I'm not sure where I got the two

My new answer should be 40.96 x 5.9 = 241.66m

I'll remember about rounding

- Physics -
**bobpursley**, Friday, October 8, 2010 at 4:40pmyes, I missed that on the time.

- Physics -
**Katherine**, Friday, October 8, 2010 at 4:47pmThanks for your help I really appreciated it!!

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