February 26, 2017

Homework Help: Physics

Posted by Katherine on Friday, October 8, 2010 at 3:59pm.

I have some questions regarding motion problems.
If I have a ball at initial velocity of 50m/s at 35 degree angle, to find horizontal and vertical components, I do the following:
Vertical is 50(sin35)=28.68-rounded to 29
Horizontal = 50 (cos 35)=40.96-rounded to 42
Maximum height ball hit 29 m/s^2 /2(9.81m/s^2)= 42.90
Range of ball:29/4.92 = 5.9 s
take 41 (horizontal velocity) times 2 =84 meters

Could you just check this for me-thank you-if its wrong, just direct me where I did it incorrectly

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