Posted by Katherine on .
I have some questions regarding motion problems.
If I have a ball at initial velocity of 50m/s at 35 degree angle, to find horizontal and vertical components, I do the following:
Vertical is 50(sin35)=28.68rounded to 29
Horizontal = 50 (cos 35)=40.96rounded to 42
Maximum height ball hit 29 m/s^2 /2(9.81m/s^2)= 42.90
Range of ball:29/4.92 = 5.9 s
take 41 (horizontal velocity) times 2 =84 meters
Could you just check this for methank youif its wrong, just direct me where I did it incorrectly

Physicsabove question please check it 
Katherine,
Just please check my calculations

Physics 
bobpursley,
Yes, I agree, but I would not have rounded to two significant figures, it pains me to to do that.

PhysicsI think I did range wrongplease check 
Katherine,
Hi, I think I did the range calculation incorrectlyShouldn't I have done:
Horizontal 40.96 times 5.9 s, not 2I'm not sure where I got the two
My new answer should be 40.96 x 5.9 = 241.66m
I'll remember about rounding 
Physics 
bobpursley,
yes, I missed that on the time.

Physics 
Katherine,
Thanks for your help I really appreciated it!!