Posted by **Eli** on Friday, October 8, 2010 at 8:59am.

A stone is dropped into a deep well and is heard to hit the water 2.95 s after being dropped. Determine the depth of the well.

- Physics -
**drwls**, Friday, October 8, 2010 at 10:52am
Solve this equation for the depth, H:

T = 2.95s = (time to fall) + (time for sound to arrive)

= sqrt(2H/g) + H/(340 m/s)

Convert it to a quadratic equation for H and solve for the positive root.

- Physics -
**Jack**, Friday, October 8, 2010 at 3:18pm
Water flows (velocity initial=0) over a dam at the rate of 660 kg/s and falls vertically 81 m before striking the turbine blades. Calculate the rate at which mechanical energy is transfered to the turbine blades, assuming 55% efficiency.

- Physics -
**Aman singla , dav bti of 9th b**, Saturday, June 4, 2016 at 9:23am
s=ut 1/2 at²

s=o(2.95) 1/2(9.8)(2.95)²

s=0 42.64

s=42.64 m (approx.)

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