an anti aircraft shell is fired vertically upward with a muzzle velocity of 200 m/sec. Compute theinstantaneous velocities at the ends of 30 & 50 seconds.
At t=30s, the velocity would be
V = 200 - 30g = -94 m/s
It will be on the way back down but will not have hit the ground yet.
At t = 50 s, V = 200 - 490 = -290 m/s
but it will have hit the ground before that, when V = -200 m/s.
Are you sure the muzzle velocity was not higher than 200 m/s? A typical value is 1000m/s
Are U Sure
yes i am sure that it is the muzzle velocity of 1000ms-1.
Pls help me solve this question
Using the sAmerican information above, when will it's height be 37.5km and interpret your result
your madness is too much. i ask a question u are asking me my response
The muzzle velocity is 100m/s
To compute the instantaneous velocities at the ends of 30 seconds and 50 seconds, we need to make use of the kinematic equation for motion with constant acceleration. The equation is:
v = u + at
Where:
- v is the final velocity
- u is the initial velocity
- a is the acceleration
- t is the time
In this case, the anti-aircraft shell is fired vertically upward, so we need to take into account the effect of gravity. The acceleration due to gravity is approximately -9.8 m/s^2 (negative because it acts in the opposite direction to the initial velocity).
Given:
- Initial velocity (u) = 200 m/s
- Acceleration due to gravity (a) = -9.8 m/s^2
Let's calculate the instantaneous velocities at the ends of 30 seconds and 50 seconds.
For 30 seconds:
- Time (t) = 30 seconds
Using the kinematic equation, we have:
v = u + at
v = 200 + (-9.8) * 30
v = 200 - 294
v = -94 m/s
The instantaneous velocity at the end of 30 seconds is -94 m/s. The negative sign indicates that the shell is moving downward.
For 50 seconds:
- Time (t) = 50 seconds
Using the kinematic equation, we have:
v = u + at
v = 200 + (-9.8) * 50
v = 200 - 490
v = -290 m/s
The instantaneous velocity at the end of 50 seconds is -290 m/s. Again, the negative sign indicates that the shell is moving downward.
So, the instantaneous velocities at the ends of 30 and 50 seconds are -94 m/s and -290 m/s, respectively.