You have a stock solution of 16.0 M {{NH}}3. How many milliliters of this solution should you dilute to make 1500 mL of 0.200 M {{NH}}3?
Well, isn't this a pickle! I'm not very good with numbers, but I'll give it a shot. To dilute the 16.0 M {{NH}}3 solution to 0.200 M, you would need to do some fancy math involving dilution equations.
Let x be the number of milliliters of the 16.0 M {{NH}}3 solution you need to dilute. According to the dilution equation, the concentration of the diluted solution times the volume of the diluted solution equals the concentration of the stock solution times the volume of the stock solution.
So, we have (0.200 M)(1500 mL) = (16.0 M)(x mL). Now, we just need to solve for x.
Are you ready for some mathematical magic? Drumroll, please...
x = (0.200 M)(1500 mL) / (16.0 M) ≈ 18.75 mL.
So, it seems like you would need approximately 18.75 mL of the 16.0 M {{NH}}3 solution to dilute and make 1500 mL of 0.200 M {{NH}}3.
To calculate the volume of the stock solution needed to make a desired concentration, you can use the formula:
C1V1 = C2V2
Where:
C1 = concentration of the stock solution
V1 = volume of the stock solution
C2 = desired concentration
V2 = desired volume
Let's plug in the values given in the question:
C1 = 16.0 M
V1 = ?
C2 = 0.200 M
V2 = 1500 mL = 1.5 L
Rearranging the formula, we have:
V1 = (C2 * V2) / C1
Plugging in the values:
V1 = (0.200 M * 1.5 L) / 16.0 M
Now performing the calculations:
V1 = (0.300 L) / 16.0
V1 ≈ 0.01875 L
Since the volume should be in milliliters, we need to convert 0.01875 L to mL by multiplying by 1000:
V1 ≈ 18.75 mL
Therefore, you need to dilute approximately 18.75 mL of the 16.0 M {{NH}}3 solution to make 1500 mL of a 0.200 M {{NH}}3 solution.
To find out how many milliliters of the 16.0 M {{NH}}3 stock solution should be diluted to make 1500 mL of 0.200 M {{NH}}3, you can use the formula for dilution:
C1V1 = C2V2
Where:
C1 = concentration of the initial solution
V1 = volume of the initial solution
C2 = concentration of the final solution
V2 = volume of the final solution
In this case:
C1 = 16.0 M
V1 = unknown (what we're trying to find)
C2 = 0.200 M
V2 = 1500 mL
Plugging the given values into the formula:
16.0 M * V1 = 0.200 M * 1500 mL
Now, let's solve for V1:
V1 = (0.200 M * 1500 mL) / 16.0 M
V1 = (300 mL * 1000 mL) / 16.0
V1 = 18,750 mL / 16.0
V1 ≈ 1171.875 mL
Therefore, you should dilute approximately 1171.875 mL (or simply 1172 mL) of the 16.0 M {{NH}}3 stock solution to make 1500 mL of 0.200 M {{NH}}3.
The dilution formula is
mL x M = mL x M