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March 26, 2017

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For f(x) = 2x-3 and g(x)= 2x^2 find,

a) (f + g)(x) = My answer is
2x^2 + 2x - 3. Is this correct?

b) (f - g)(x) How would you do this?

c) (f X g)(2) I do not know what to do since the 2 is there.

Determine whether the graph of the following equation is symmetric with respect to the x-axis, the y-axis, and the origin.

y^2 - x - 49 = 0

For x axis -y^2 - x - 9 = 0 is not the same as the first equation so it is not symmetrical to the x-axis. Correct?

For the y-axis y^2 + x - 49 = 0 is not the same as the first equation so it is not symmetrical to the y-axis. Correct?

For the origin -y^2 + x - 49 = 0 is not the same as the first equation so itis not symmetrical to the origin either. Am I correct?

  • Math(Please, Please, help) - ,

    Nevermind,I did not realize that my question was already answered.

  • Math(Please, Please, help) - ,

    b) the same way you did a) , except ..
    2x - 3 - (2x^2) =
    (f-g)(x) = - 2x^2+ 2x - 3

    c) in this case you multiply,
    (fxg)(x) = (2x-3)(2x^2

    then fxg(2) = (4-3)(8) = .... (I just replaced the x with 2)

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